LKS Science

KineLab 2nd Order Kinetics

Heterogeneous Reaction Kinetics Engine: A(s) + 2B(aq) → C(aq)

Speed:
0s 300s
Time t = 0.0 s
Span:

Condition Set 1

Reference
1.00 M
0.50 L
25.0 °C
1.00x
Morphology: Coarse Pellets
keff
0.0131
r0 (Initial)
0.0131 M/s
Max Yield C
0.250 mol

Condition Set 2

Comparative
1.00 M
0.50 L
40.0 °C
2.00x
Morphology: Fine Powder
keff
0.0624
r0 (Initial)
0.0624 M/s
Max Yield C
0.250 mol
Physical Reactor Simulation Bubbling & Color Shift ∝ Rate & Concentration
Set 1 25.0°C
C: 0.00 mol
Set 2 40.0°C
C: 0.00 mol

Kinetic Charting Engine

Set 1 Current: 0.000 mol
Set 2 Current: 0.000 mol

Kinetic Target Challenge Game

Optimize Set 2 reaction conditions to meet specific product yield & kinetic targets under physical constraints.

Level 1: Yield Master Target: Product Yield

Produce at least 0.35 moles of C within 40 seconds using Set 2 parameters.

Target Time: 40 s
Target Amount C: ≥ 0.350 mol
Constraints: T ≤ 35°C, V_B ≤ 1.0L
Challenge Evaluation
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Set 2 Configuration Sliders

Molarity [B]0 1.0 M
Volume VB 0.5 L
Temperature T (°C) 25 °C
Surface Area Factor 1.0x

Numerical Data Inspector

Time-series kinetic data sampled across simulation runtime.

Time (s) Set 1 nC (mol) Set 1 [B] (M) Set 1 Rate (M/s) Set 2 nC (mol) Set 2 [B] (M) Set 2 Rate (M/s)

Heterogeneous Chemical Kinetics Theory

Mathematical and physical foundations of the $A(s) + 2B(aq) \rightarrow C(aq)$ reaction.

1. Integrated Rate Law (2nd Order in B)

For the elementary step A(s) + 2B(aq) → C(aq) with rate law r = keff[B]2:

d[B] / dt = - 2 · keff · [B]2
Integrating from t = 0 to t yields:
[B](t) = [B]0 / (1 + 2 · keff · [B]0 · t)

The yield of product C in moles is:

nC(t) = (keff · VB · [B]02 · t) / (1 + 2 · keff · [B]0 · t)

2. Arrhenius Equation & Temperature

The rate constant k increases exponentially with absolute temperature T (K) according to the Arrhenius equation:

keff = Apre · exp(-Ea / (R · T)) · SAratio
  • Apre: Pre-exponential frequency factor ($10^6\text{ L/mol}\cdot\text{s}$)
  • Ea: Activation Energy ($45,000\text{ J/mol}$)
  • R: Universal Gas Constant ($8.314\text{ J/mol}\cdot\text{K}$)

3. Heterogeneous Surface Area Effect

Because Reactant A is a solid phase and Reactant B is aqueous, collisions can only occur at the solid-liquid interface.

Subdividing solid A into fine powders or nanoparticles dramatically increases the exposed surface area per unit mass, multiplying effective collisions and scaling $k_{\text{eff}}$ directly.

4. Second-Order Half-Life & Max Yield

Unlike 1st order reactions, the half-life of a 2nd order reaction depends inversely on the initial concentration:

t1/2 = 1 / (2 · keff · [B]0)

The theoretical maximum yield of product C as $t \rightarrow \infty$ is limited by the initial moles of reactant B: nC,max = (VB · [B]0) / 2.